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Created with Fabric.js 1.4.5 6 [0, ) for a predefined infographic start by dragging a theme onto the canvas your artboard start from scratch[clears the canvas] when your ready donot forget to save your visual. SQUARE ROOT FUNCTIONS PATE BY KENNEDY DOMIAN END BEHAVIOR ( , ) [0, ) TIMES BORO & DONCASTERHAVE GONE HEAD TO HEAD IN ALL COMPETITONS 28th SEPTEMBER 1901 BROWN RANGE BORO 0 6 GOALS FROM JONES, TENNANT, TURNER, WARDROPEAND A DOUBLE FROM BREARLEY ENSURED A LINTHORPE ROAD CROWD OF 10,638 WENT HOME HAPPY BORO ARE UNDEFEATED AT HOME, IN THE LEAGUE, TO DONCASTER BRIAN CLOUGH ISBORO'S TOP SCORERV DONCASTER DONCASTER RVRS. BIGGEST VICTORY BORO HAVE NEVER HAD A MAN SENT OFF v DONCASTER BORO V DONCASTER FORM 17th 16th 11 GAMES12 POINTS 12 GAMES12 POINTS TRANSFORMATIONS D IN ALL COMPETITIONS POSITION IN THE LEAGUE < MOST RECENT > L L W IN THE LAST 4 L W L W 4 TOP SCORER 4 ADOMAH 4 TRANSFORMATIONS double click to changethis text! Drag a cornerto scale proportionally. ( , ) July June May April March February January EQUATION :f ( X ) = x double click to changethis text! Drag a corner PATE kf(x) = y=5 when x=1 which made the line steeper-kf(x) = flipped kf(x) upside downf(kx) = is inbetween of f(x) and kf(x)f(-kx) = f(kx) was flipped backwardsf(x) +k = the line started at (0,5)f(x) - k = the line moved down 10 units and starts at (0,-5)f(x+k) = the line starts at (-5,0)f(x-k) = the line is moved 10 units to the right so it starts at (0,5) kf(x) = kf(x) = y+ 1 when x =.5 and that makes the line less steep-kf(x) = kf(x) gets turned upside down f(kx) = y=.5 when x=.5 but then the line begins curving lessf(-kx)= f(kx) gets flipped backwards f(x) +k = the line starts on (0,.5)f(x) -k = the line gets moved down 1 unit and starts at (0,-.5)f(x+k) = the line starts at (-.5,0)f(x-k) = the line moves right 1 unit and starts at (.5,0) 0 20 40 60 80 100 January February March April May June July x y 5 2.210 3.1615 3.8725 5
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