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Created with Fabric.js 1.4.5 Pt = the power used to heat the water in kWh. L = the number of liters of water that is being heated ∆T = the difference in temperature between hot water ended up and the cold water started in degrees Celcius. As a result, themolecules become apart as their potential and kinetic energies get increased and water gets converted to the gaseous state. By combining formula and formula and substituting specific heat of water value for the constant, the formula below is produced: Pt = (4.2 x L x ∆T)/3600 Time taken at boiling point of water, t = Heating Rate, Pt (KWh)/Heater Element Rating (kW) Assume heating 20L of watert(0)=20Ct(60)=100CGiven, element heater rating used is 3.6 kW. Therefore,Determine the heating rate (Pt)?time taken (t) to heat the water until water reach boiling point? Solution: By using the formula, Pt = [4.2 x 20 x (100-20)]/3600 = 1.867 kWh Time taken, t = Pt/ Heater Element Rating = 1.867kWh/3.6kWt = 0.52 hoursTherefore, It will take 0.52 hours to heat 20L of water, with an element with a rating 3.6 kW. 1 kWh = 3.6 MJ1 Joule = 1 Watt/sKnowing that, 1000 Watts in a kW 3600 second in an hour. m = the mass of the subtances (kg). Note that the mass of water is 1 kg per litre, so number of litres (L) to be heated can be substituted here. C = specific heat of water is 4.2 (kJ/kg/K) ∆T = the change of temperature GROUP Problem Description. Heating Rate (Pt) =Heat Energy/Time= Q/t = mC ∆T/t Generally, the problem is to estimate the duration (time taken) for water to boil in two differentcontainer.The main idea is to make a guess how long we think it will take water to boil. Therefore, some formula should be produced to approximate boiling duration. This idea required amount of heat energy and the rate at which energy is being pumped in to predict how much time that the process should take. hotlunchtray.com 2013 FORMULA Where Q = amount of heat energy (Joules) RECOMMENDED SOLUTION Methodology Differential Equation selection include assumptions and all theparameter/variables is describe that associated in the equation Pt = (4.2 x L x ∆T)/3600 double click to changethis text! Drag a cornerto scale proportionally. 1 2 HOT WATER POWER CONSUMPTION INDICATOR CONCLUSION i ii i ii Temperature will only increase as long as heat gain exceeds heat loss. raised its temperature to 100 degrees celcius. we can determine how much heat energy that amount of water need to get to boiling temperature.
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